Date: MATH 1210-4 - Spring 2004
The only problem that could have is a 0 in the denominator. But is at least , so is never 0, and the function has no problem. Therefore .
The only problem that could have is a 0 in the denominator. Then, , so the only problem that the function has is at . Therefore .
This function has problems when the numbers inside the root are negative. So, if (better, ), there are no problems. Thus .
First, we remember that . Then, since we know that and we conclude
We have to find if there is a relation between and .