Quiz 7 (Solution)


Date: MATH 1090-4 - Fall 2003

  1. Match each of the following descriptions with the corresponding graph shown in Figure 1. No justification required!
    i.
    A rational function with vertical asymptotes.
    ii.
    A piecewise defined function.
    iii.
    A polynomial of degree $ 3$.

    Figure 1: Graphs for exercise 1
    []\includegraphics[scale=.3,angle=0,
clip= true]{q7-f2.eps} []\includegraphics[scale=.3,angle=0,
clip= true]{q7-f0.eps} []\includegraphics[scale=.3,angle=0,
clip= true]{q7-f1.eps}

    Graph (b) is the only graph with vertical asymptotes, so it corresponds to a rational function (with vertical asymptotes). Graph (a) is composed of two parts (a parabola and a line), so that it corresponds to a piecewise defined function. Graph (c) corresponds to a polynomial of odd degree, so it is the polynomial of degree $ 3$.

  2. Identify any vertical asymptotes of $ f(x)=\frac{2x+4}{x+1}$.

    Vertical asymptotes in rational functions appear when the denominator vanishes. In this case, $ x+1=0 \ensuremath{\Rightarrow}\xspace x=-1$, so that the only vertical asymptote happens at $ x=-1$.

  3. Let

    $\displaystyle A=\left[ \begin{array}{ccc} 1 & -1 & 2\\ 4 & 0 & 1 \end{array} \r...
...d{array} \right] \quad D=\left[ \begin{array}{c} 2\\ -7\\ 6 \end{array} \right]$    

    1. Write the size of each of the four matrices.

      $ A$ is $ 2\times 3$; $ B$ is $ 2\times 2$; $ C$ is $ 2\times 2$; $ D$ is $ 3\times 1$.

    2. Perform each of the following operations whenever possible. If it is not possible, say so.
      1. $ A^t$.

        Each row of $ A$ becomes a column:

        $\displaystyle A^t = \left[ \begin{array}{cc} 1&4\\ -1&0\\ 2&1 \end{array} \right]$    

      2. $ A+B$.

        It is not possible because $ A$ and $ B$ have different sizes.

      3. $ B-C$.

        $\displaystyle B-C = \left[ \begin{array}{cc} 0&1\\ 1&0 \end{array} \right] - \l...
...&0 \end{array} \right] = \left[ \begin{array}{cc} 1&0\\ 2&0 \end{array} \right]$    

      4. $ D+D$.

        $\displaystyle D+D = \left[ \begin{array}{c} 2\\ -7\\ 6 \end{array} \right] + \l...
... \end{array} \right] = \left[ \begin{array}{c} 4\\ -14\\ 12 \end{array} \right]$    



Javier Fernandez 2003-10-22