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Some Additional Experiments

Javier Fernandez


Department of Mathematics
University of Utah
Salt Lake City
UT 84112

jfernand@math.utah.edu

The purpose of this note is to report on a very simple experiment. Let $ C$ be an elliptic curve over $ \ensuremath{\mathbb{Q}}$. By Mordell's Theorem we know that, as a group, $ C \simeq \ensuremath{\mathbb{Z}}^r \oplus T$, that is it contains infinitely many rational points if $ r$, the rank, is positive.

Now, consider the reduction of the curve $ C$ to $ \ensuremath{\mathbb{Z}}_p = \ensuremath{\mathbb{Z}}/(p\ensuremath{\mathbb{Z}})$, and let $ N_p = \char93  C(\ensuremath{\mathbb{Z}}_p)$. By Hasse's Theorem we know that

$\displaystyle \vert p+1 - N_p \vert <2\sqrt{p}$    

so that, roughly speaking, $ N_p \sim p+1$. In order to understand how $ N_p$ differs from this ``expected value'' we will consider the ``density'' $ D_p = \frac{N_p}{p}$.

Morally, at least, a curve with many rational points (that is, large $ \char93  C(\ensuremath{\mathbb{Q}})$), is expected to have many points over $ \ensuremath{\mathbb{Z}}_p$. We want to show this with a few examples. We will consider curves of the form

$\displaystyle y^2 = x^3 + a x^2 + bx +c$    

with $ a$, $ b$ and $ c$ as shown on Table 1

Table 1: Elliptic curves
Curve $ a$ $ b$ $ c$ rank
$ C_0$ 0 $ 1$ 0 0
$ C_1$ 0 $ 13$ 0 $ 1$
$ C_2$ 0 $ 14$ 0 $ 2$
$ C_3$ $ 337$ $ 337^2$ $ 337^3$ $ 3$
$ C_{14}$ 0 $ 402599774387690701016910427272483$ 0 $ 14$


The following function, in some sense, measures how much $ N_p$ deviates from the ``medium value'' $ p$.

$\displaystyle F(x) = \prod_{p \leq x, p\, prime} \frac{N_p}{p}$    

Figure 1 shows the graph of $ F$ corresponding to the curves $ C_0$ and $ C_1$.

Figure 1: Graph of $ F(x)$ for $ C_0$ (below) and $ C_1$ (above)
\includegraphics[scale=.5,angle=0,
clip= true]{f01.eps}

As you can see, there is a significant difference between the behavior of the two curves. As expected, $ C_1$ seems to have more points than $ C_0$, perhaps reflecting the fact its rank is $ 1$ while that of $ C_0$ is 0. Actually, using Nagel-Lutz's Theorem it is easy to check that $ C_0(\ensuremath{\mathbb{Q}}) \simeq \ensuremath{\mathbb{Z}}_2$.

Next we see what happens as we consider curves of higher rank. Figure 2 shows the graph of $ F$ for $ C_1$, $ C_2$ and $ C_3$.

Figure 2: Graphs of $ F(x)$ for the curves $ C_1$ (bottom), $ C_2$ (middle) and $ C_3$ (top)
\includegraphics[scale=.5,angle=0,
clip= true]{f123.eps}

We see that, again, all functions are, roughly, increasing and that the curves with higher rank have significantly bigger values of $ F$. Notice the scale on the $ F$-axis, compared to Figure 1.

Last, Figure 3 shows the graph of $ F$ for $ C_{14}$. Again, notice the scale on the $ F$-axis and thus, how much bigger the values of $ F$ are compared with those of the other curves.

Figure 3: Graph of $ F(x)$ for the curve $ C_{14}$
\includegraphics[scale=.5,angle=0,
clip= true]{f14.eps}

To conclude, let me mention that the function $ (F(x))^{-1}$ of the elliptic curve $ C$ is somehow related to the value of the $ L$-function, $ L(C,1)$. Thus, we see that for a curve of rank 0, the limiting value of $ F(x)^{-1}$ is a non-zero number. On the other hand, for all the other curves (with rank $ >0$) $ F(x)^{-1}$ seems to approach to 0. In fact, the bigger the rank, the faster $ F(x)^{-1}$ approaches 0. As you have guessed, this is the content of the Birch and Swinnerton-Dyer Conjecture that says that the order of the zero of $ L(C,s)$ at $ s=1$ should compute the rank of the curve $ C$.




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Javier Fernandez 2003-06-24